Which point lies on the graph of the following piecewise function? y = x^2 if x <= 0 y = x + 1 if x > 0
need the graph
(–1, 0) (1, 1) (0, 1) (–2, 4) Those are the options but there is no graph
even if you can help me know how to know which point lie on the graph that would be a big help
ahh wait you can draw it
|dw:1340437869972:dw|
that is your piecewise function
(-1,0) does not lie o your graph also if x<=0 you use x^2=f(x)=y so 0=1 which is false
so im guessing (0,1) or (-2,4)
next (1,1) 1=2 not true
(0,1) since it is equal to 0 you use the first equation 1=0^2 which is 0, so not true
lastly (-2,4) it's less than 0 use first equations 4=-2^2=4
(-2,4
wow this is easier than im making it....i dont know what i was trying to do but you made it much easier i can actually do the others myself know thank you!
*now
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