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Integrating... (missing some kind of trig-related trick here) \[\int 5\cdot sin(8x)\cdot cos(5x)\cdot dx \] (medal for showing related substitutions :-) )
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∫5⋅sin(8x)⋅cos(5x)⋅dx
a trig identity should solve your problem here\[\sin a\cdot\cos b=\frac12[\sin(a+b)+\sin(a-b)]\]
for future reference, I keep this file handy at all times http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
Ah... Ty @TuringTest :-)
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