Question

Use the substitution method to solve the following system of equations.
x + y = 3
2x + 2y = 10

Answer 1

\[\huge{x+y=3}\]
\[\huge{x=3-y}\]

2x+2y = \(\huge{2(3-y)+2y=6-2y+2y = 6 }\) hence no solution

Answer 2

note that 2x+2y = 2(x+y) = 2(3) given x + y =3 hence 6 = 2x+2y but given 2x+2y = 10 that is not possible

Answer 3

not possible...ansr cms only with slope form