Solve: x^(x^(x^(x^(x^....)))) = 3
x^3 = 3 u see.. its just this. solve for x now
we have this simplified form : x^3 = 3 solve for x.. (assuming x tends to infinyt)
infinity**
Thats right. But x have not only one solutions.
how about x^(x^3) = 3 or x^3 (ln x) = ln 3 i dont know how we can solve this one : but this will surely give another value of x
Not x^(x^3) = 3. x^3 * x^3 =3 Another value of x is 3^(1/9) And actually there are infinite number of solutions of x. out of which x^(1/3) is the largest.
x^3 . x^3 = 3 ??? you sure ??? i hope its not (x^x).(x^x)..... ?
Sorry. My mistake
hmm,,so that requires the knowledge of interpolation to solve for further values of x. and yes,,must be infinite values of x
x^(3^3)
x^(3^(3^(3)))
and so on
if you have already substitued that much part to be 3..you have nothing left(ofcorse) i mean 3^3 is not valid..and also further ones are not valid
u asking if this can look like this : \[\huge{x^{x^3} = 3 }\] ?
infinity never ends
your logic is wrong buddy @sauravshakya ,,please re-think.. zabardasti solve kar rahe ho..
3^(1/9) and 3^(1/27) both are valid
ofcorse not!! hmm,,
i think she is correct.. @shubhamsrg .. can you explain my above expression... im confused after putting that :(
x^(x^3) = 3..yes thats fine.. and not x^(3^3) <---this is humbug! :P
i mean, her question is valid... 1/9 is ofcourse not equal to 1/27 !!
ahh.. i see now... thanks @shubhamsrg ;)
I will return..... With a proof
hmmm..
The proof is simple. Since x^(x^(x^(x^(x^....)))) = 3, s^[x^(x^(x^(x...))))] =3, or x^3 =3
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