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Multiply (w+t)(w^2-wt+t^2)=
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w^3-w^2t+wt^2+tw^2-wt^2+t^3 =w^3+t^3
Can you show me how you came up with that. I got a different answer that is why I ask.
1st multiply with w frm 1st barckt to anather brckt ull get=w^3-w^2t+wt^2 den multiply wd t frm 1st brckt to anather brcket ull get= tw^2-wt^2+t^3 den add both of dem as ders addition in 1st brcket ull get=w^3-w^2t+wt^2+tw^2-wt^2+t^3 now -w^2t will get cancelled with +w^2t as they hav opposite signs and wt^2 will get ancelled wd -wt^2 so finally ull get =w^3+t^3 as an ans.
|dw:1340573908956:dw|when we multiply something like this out we \(distribute\) each term from the parentheses, then add them all up...
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