Question

When the sum of a number plus 3 is squared, it is 11 more than the sum of the number plus 2 when squared.

Answer 1

sum of a number plus 3
\(x+3\)
squared
\[(x+3)^2\] the sum of the number plus 2 squared
\[(x+2)^2\]
first one is eleven more than the second
\[(x+3)^2=(x+2)^2+11\] solve for \(x\)

Answer 2

make sure to square correctly i.e. \((x+3)^2=x^2+6x+9\) and \((x+2)^2=x^2+4x+4\)

Answer 3

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