3. A solution containing 45% water is mixed with another solution containing 10% bromine. If the chemist needs 30 liters of the mixture, how many liters of each solution are needed to make a 34.5% water/bromine solution?

I got this as my system of equations-
.45x+.10y=3
x+y=30
Could anyone check this for me?

Question

3.	A solution containing 45% water is mixed with another solution containing 10% bromine. If the chemist needs 30 liters of the mixture, how many liters of each solution are needed to make a 34.5% water/bromine solution?

I got this as my system of equations-
.45x+.10y=3
x+y=30
Could anyone check this for me?

ganeshie8 · Answer

is your first equation :
$$\huge.45x+.10y= 3$$

?

how you got 3 on RHS ?

anonymous · Answer

I did .10bromine *3. Just realized that's wrong.

ganeshie8 · Answer

ok.. other than that, equations look perfect.. go ahead and solve... :)

anonymous · Answer

Wait would the 3 be wrong? and would I do 34.5(30) right?

anonymous · Answer

And I got the 3 by .10(30)

anonymous · Answer

.45x+.10y=10.35

anonymous · Answer

Okay so that's what it would be right? I wasn't so sure.

anonymous · Answer

Yeah it would be .345(30) not 34.5

anonymous · Answer

Yes I just noticed that, but that's instead of the 3. Tyvm :)

anonymous · Answer

And it equals 10.35

anonymous · Answer

Tyvm :)

hero · Answer

.45x + .10y = 10.35
    x  +     y = 30