Violet runs on a triangular track in a local park. On Saturday, she runs one lap around track BAC. The length of each path on this track is shown in meters (m) in the diagram below. If track DEF is similar in shape to track BAC, how many meters, rounded to the nearest tenth, would Violet run in one lap on track BAC? Type the numeric answer only in the box below.
@sugargurl :P
sorry dear @courtneycara17 i cant figure it out..;( i m always confused with the problem solvings i m really sorrie..;(
you'll need to pay attention to the correspondence here so you can set up the proportions accurately. \[\huge DEF \sim BAC \]
solve this.... cross multiply... \[\large \frac{18}{x}=\frac{12}{27} \]
^^^that's to get AC. x = AC
12x = 18*27
?
@timo86m can u help
12x = 18*27 sfx like this
12x=486 expand right hand side x= 40.5 divide by 12 it is 41 rounded up
Now continue on to get the answer.
You need to find enough to calculate the perimeter.
Use the same reasoning to calculate BC
12:18::18:x 12x=18*18 12x=324 x=27 or BC=27 Now you have all three sides for track ABC, 18, 27 and 40.5 meters Perimeter is 18+27+40.5=85.5 or 85.5 to the nearest tenth meters
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