Question

x^2/3-2^1/3-2=0

Answer 1

that's a nice equation... what are we supposed to do with it?

Answer 2

"solve" is my instruction

Answer 3

Is that supposed to say:
\[x^{\frac{2}{3}}-2^{\frac{1}{3}}-2=0\]

Answer 4

yes

Answer 5

Ok, so fractional exponents can be written in a couple of different ways:
\[X^{\frac{2}{3}} = (X^{2})^{\frac{1}{3}} = (X^{\frac{1}{3}})^{2} = \sqrt[3]{X^{2}} = (\sqrt[3]{X})^{2}\]

So with your equation you could write: \[(X^{2})^{1/3}-2^{1/3}-2=0\]

Answer 6

ok, there is still something basic I am not remembering here, and my apologies it is not -2^1/3 it is 2x^1/3. I appreciate your help

Answer 7

Ok, makes a lot more sense then lol!
\[(X^{1/3})^{2}-2X^{1/3}-2=0\]
\[Y=X^{1/3} = \sqrt[3]{X}\]
\[Y^{2}-2Y-2=0\]

Solve for Y, then solve for X.

Answer 8

thank you so much

Answer 9

No problem at all.

Answer 10

I have another one. Square root of x+36=x-6

Answer 11

my instruction again is "solve".

Answer 12

Please select best answer if you deem it so, and please start a new question for each question.