Question

it a and b are roots of equation 3x^2 - x + 8=0 the equation whose roots are 1/(a+2) and 1/(b+2) is?

Answer 1

let second eqn be x^2 + px + q =0
for the second eqn,,
sum of roots = 1/(a+2) + 1/(b+2) = (a+b)+4/ (ab + 2(a+b) +4) = -p
product of roots = 1/a+2 * 1/b+2 = 1/ (ab + 2(a+b) +4) =q

from 1st given eqn,,we know a+b = 1/3 and ab =8/3
just substitute these values to find p and q and thus the req eqn

note:alternative method would be to find a and b and then using it find 2nd eqn.

Answer 2

@satellite73

Answer 3

ohh lol.. :|

Answer 4

di nt understand

Answer 5

a +b = -b/a that method lol

Answer 6

sum of roots things..hmm..

Answer 7

yuo

Answer 8

can u solve by that

Answer 9

i used that method only buddy!! hehehe
alternative which i suggested was some other method :D

Answer 10

thxx