Question

if the equation a^2t^2 - act + a =0 has x and y as roots then (x-y)^2=?

Answer 1

If you notice, this is a quadratic in 'a'.
that means, sum of roots:
x+y = -ct/t^2
and product of roots =
xy = 1/t^2


now,
\[(x-y)^2 = x^2 + y^2 - 2xy = x^2 + y^2 + 2xy - 4xy = (x+y)^2 - 4xy\]

Answer 2

dum of roots x + y = (ac) / a^2 = c/a
xy = a / a^2 = 1 / a
plug these values into what apoorvk got and you have your answer

Answer 3

* sum of roots

Answer 4

dumb of the roots sounds better

Answer 5

lol

Answer 6

Lol!

Answer 7

thxxxx

Answer 8

yw