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OpenStudy (apoorvk):
You mean:
\[\frac{3}{4x} + 1 = -8\]
OR
\[\frac{3x}{4} + 1 =-8\]
Which one?
OpenStudy (anonymous):
|dw:1340716760036:dw|3/4x
OpenStudy (diyadiya):
\[\frac{3}{4}x + 1 = -8\]First subtract 1 on both sides, can you?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
-9
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OpenStudy (diyadiya):
what about the left side f the equation ? :D
OpenStudy (anonymous):
i dont know
OpenStudy (diyadiya):
\[\frac{3}{4}x+1=-8\] we are trying to isolate x \[\frac{3}{4}x+1-1 =-8 -1\]\[\frac{3}{4}x =-9\]
since 1-1=0
understood so far?
OpenStudy (anonymous):
yes
now i mulitpy 4?
OpenStudy (diyadiya):
Right :D
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OpenStudy (diyadiya):
what do you get?
OpenStudy (anonymous):
-36
OpenStudy (diyadiya):
where's the otherside of the equation? :O
OpenStudy (anonymous):
12?
OpenStudy (apoorvk):
12 what? 12 watermelons?
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OpenStudy (apoorvk):
There is supposed a Mr. 'x' along with coefficient '12', don't you forget to bring him along, or he will get very mad, and get you a wrong answer. -.-
OpenStudy (diyadiya):
well this is how you get it
\[\frac{3}{4}x = -9\]multiply "both" sides by 4\[\frac{3}{4}x \times 4= -9 \times 4\]\[\frac{3}{\cancel{4}}x \times \cancel{4}= -9 \times 4\]\[3x = -9 \times 4 \]\[3x = - 36\]
Now can you divide "both" sides of the equatio by three and show me?