solve the formula for area of a trapezoid. A = h(b1 + b2/2) for b1
\[A= h( \frac{b1+b2}{2})\]first multiply both sides by 2 can you do that?
You mean: \[A = h(\frac{b_1 + b_2} 2) \] where \(b_1~ and~b_2\) are length of parallel sides, and 'h' is the height right? Can you just rearrange the whole thing, to write it in terms of \(b_1\) solely?
That is what I meant.
I mean, to write it *implicitly* for \(b_1\).
\[2 \times A = 2 \times h \left( \frac{b1+b2}{2} \right)\]\[2 A = \cancel{2} \times h \left( \frac{b1+b2}{\cancel{2}} \right)\]\[2 A = h \left( {b1+b2} \right)\] Can you continue from here?
yeah thanks.
I mean it's still kind of confusing..
Welcome!! But what will be the next step?
well the answer is for b1
I have no clue :(
lets go step by step though did you understand till this part?
yeah pretty much
Sure?
Please do ask if you haven't got any specific step!
yes
I get it to this part.
ok so, 2A = h(b1 + b2) Now next step is to divide both sides by 'h' can you do that?
is it b1 = a/h?
Nope, don't be in a hurry! do the step i told you to do :)
okay okay :P
??
yeah I can only do so much for an 8th grader lol
Im in an advanced math and i'm horrible at it.
Its just division just divide both sides by h for example when you have c = bk and when you divide both sides by k you get c/k = bk/k c/k = b just like that! |dw:1340720387237:dw|
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