Please don't solve. \[\sum_{n=1}^{\infty} \frac{(2n+1)^{n}}{n^{2n}}\] I was wondering if you can give me hint on what method i should use to test for convergence. I tried diving by n...but I feel like I'm not doing the division right. \[\frac{{(2+\frac{1}{n})}^{n}}{1}\]
root test
just curious, how did you come to that conclusion?
i cannot speak for zarkon, but i would say because everything is being raised to a power of \(n\) and so it is natural to take the nth root if you had factorials the ratio test would come to mind because terms tend to cancel
\[a_{n} = \left( \frac{2n+1}{n^{2}} \right)^{n}\] \[\frac{2}{n} =0\] convergent?
lim n-> \[\infty\]
is this a different question?
no the same...what did i do wrong?
i see..... im supposed to see if L < or > or = 1 right?
oh i see i wasn't paying attention nth root is \[\frac{2n+1}{n^2}\]
take the limit as \(n\to \infty\) and get 0, so you are in good shape (i.e. converges)
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