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Mathematics 8 Online
OpenStudy (anonymous):

How do you solve this..?

OpenStudy (anonymous):

\[16t ^{2}-100t+76\]

OpenStudy (anonymous):

there needs to be an equation in order for it to be solved...

OpenStudy (anonymous):

Do you see it? I put it up there @dpaInc

OpenStudy (anonymous):

lol, sorry i may need thicker glasses... but i can't find it.......

OpenStudy (anonymous):

16t^2-100t+76

OpenStudy (anonymous):

oh... i mean an equation.... there is no equal sign.... so nothing to solve... it's like saying this... solve: x+3

OpenStudy (anonymous):

how do you solve x+3 ?

OpenStudy (anonymous):

Oh well, I didn't think that it was necessary to put the equal sign because we've done so many equations, I assumed you would have known.

OpenStudy (anonymous):

the question is how to factor it

OpenStudy (anonymous):

x+3? Isn't it -3?

OpenStudy (anonymous):

it makes a big difference... solve: x+3=5 solve: x+3=0 they have different solutions...

OpenStudy (anonymous):

x=2,-3

OpenStudy (anonymous):

okay but he wants to know... what is the equation equal too....

OpenStudy (anonymous):

but how do you know which one is the correct one if i didn't specify ?

OpenStudy (anonymous):

How does this relate to my equation?

OpenStudy (anonymous):

you do not have an equation...

OpenStudy (anonymous):

because if we have it something to equal too, we can actually solve for t... if not it's just nothing...

OpenStudy (anonymous):

16t^2-100t+76=0 -.-

OpenStudy (anonymous):

well now that changes everything... Well you cannot solve for t... i tried it for is and it won't give you any straight up whole numbers...

OpenStudy (anonymous):

So do you use the quadratic formula?

OpenStudy (anonymous):

if you can't factor, yes, quadratic forumula or complete the square.:)

OpenStudy (anonymous):

\[100\pm \sqrt{100^{2}-4(16)(76)}/2(16)\]

OpenStudy (anonymous):

?

OpenStudy (anonymous):

yep...

OpenStudy (anonymous):

It's not a perfect square right?

OpenStudy (anonymous):

nope...... ugly numbers...:(

OpenStudy (anonymous):

is this question a part of a bigger question?

OpenStudy (anonymous):

No, thank goodness, haha

OpenStudy (anonymous):

i asked because your coefficients look like it had something to do with projectiles....

OpenStudy (anonymous):

Ah, no :P

OpenStudy (anonymous):

but in projectiles, the 16 is actually a negative 16....

OpenStudy (anonymous):

ok... good work sakigirl...:)

OpenStudy (anonymous):

remember to solve your EQUATIONS...:)

OpenStudy (anonymous):

Haha, alright :P Thank you

OpenStudy (anonymous):

yw...:)

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