Question

Do you use the quadratic formula for this equation?

Answer 1

\[2x ^{2}+3x-6\]

Answer 2

That's how I would do it

Answer 3

Yes we can use quadratic formula for this equation...

Answer 4

\[2x ^{22}+3x-6=0\]

Answer 5

I meant to the power of 2

Answer 6

Yes, we can solve it by quadratic formula..
You want to know how???

Answer 7

Yes.

Answer 8

See, the general form of Quadratic equation is:
\[ax^2 + bx + c = 0\]

Got or not??

Answer 9

\[x= (-b+-\sqrt{b^2-4ac})/2a\]

Answer 10

Yes, I get it, but you use the formula @nphuongsun93 gave, and using that formula is a bit tricky for me

Answer 11

I am explaining it to sakigirl @nphuongsun93 ..

Answer 12

What is the value of D you found @sakigirl ??

Answer 13

If it's quadratic, I can use it's formula aye!

Answer 14

quadratic formula:
\[\large \frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2a} \]
for the question.
\(2x^2+3x-6\) => \(a=2,b=3,c=-6\)
then sub it in

Answer 15

Thanks Omniscience...

Answer 16

THE QUADRATIC FORMULA:
(can be used for any equation of degree '2', i.e. quadratic!)

Hmm compare your quadratic equation to the standard equation \(ax^2+bx+c=0\), and find out 'a', 'b' and 'c' for your particular equation.

Now the quadratic formula is:
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]


Substitute the obtained values of 'a', 'b' and 'c' in the equation, calculate and enjoy!

Answer 17

That '\(b^2 - 4ac\)' is also called the 'D', D for DISCRIMINANT!

Answer 18

\[\large \color{red } {\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2a} }\]
a more colourful quadratic formula :P

Answer 19

See, for using quadratic formula first find the value of D..
D is called the Descriminant..

It is given as :

\[D = b^2 - 4ac\]

Once you find D, then find its square root..ie
\[\sqrt{D} = \sqrt{(b^2 - 4ac)}\]

Now the formula becomes quite simple:

\[x = \frac{-b \pm \sqrt{D}}{2a}\]

Put all the values in this formula and get the answer...

Answer 20

So, you got D = 57

So, you have problem in taking square root of this...

Answer 21

Just leave as such you cannot solve it further...
\[\sqrt{D} = \sqrt{57}\]

Answer 22

Well, thank you! I'm finally done! :)

Answer 23

Welcome dear..

Answer 24

Did somebody just talk about colors?
\[\color{purple }{\normalsize x}\color{red}{\normalsize\text{=}}\frac{\color{red}{\normalsize\text{−}}\color{orange}{\normalsize\text{}}\color{#9c9a2e}{\normalsize\text{b}}\color{green}{\normalsize\text{}}\color{blue}{\normalsize\text{±}}\sqrt{\color{purple}{\normalsize\text{}}\color{purple}{\normalsize\text{b}}\color{red}{\normalsize\text{}}^{\color{orange}{\normalsize\text{2}}}\color{#9c9a2e}{\normalsize\text{−}}\color{green}{\normalsize\text{4}}\color{blue}{\normalsize\text{}}\color{purple}{\normalsize\text{a}}\color{purple}{\normalsize\text{}}\color{red}{\normalsize\text{}}\color{orange}{\normalsize\text{c}}}\color{#9c9a2e}{\normalsize\text{}}\color{green}{\normalsize\text{}}}{\color{blue}{\normalsize\text{2}}\color{purple}{\normalsize\text{a}}\color{purple}{\normalsize\text{}}} \]