Question

find the consecutive even integers such as the first times the third is 2 greater than 5 times the second.

Answer 1

pls answer I really need help

Answer 2

if they are a-1,a and a+1
then
(a-1)(a+1) = 2 + 5(a)
just solve for a

Answer 3

how to solve for the a

Answer 4

simplify LHS,,,what do you get ?
NOTE: LHS MEANS LEFT-HAND-SIDE!!
:P

Answer 5

sorry i dont know how LHS works

Answer 6

you know how to solve quadratic eqns atleast ?dont you ?

Answer 7

can you solve it pls

Answer 8

yes i can,,but i wont..
how about i ask you the same ques? :P

Answer 9

Let the numbers be 2n,2n+2,2n+4
then according to the given data
2n(2n+4) -2=5(2n+2)
4n^2+8n -2=10n+10
4n^2-2n-12=0
2(2n^2-n-6)=o
now apply the quadratic formula
\[(-b +/- \sqrt{b^2 - 4ac}) \div 2a\]
we get the values of n to be 2,-3/2
taking +ve value of n
we get the numbers 4,6,10

Answer 10

sorry the numbers are 4,6,8

Answer 11

ohh i never noticed it said "even" ..hmm..sorry then :P

Answer 12

hahaha.. carl.. pang college na ung sinagut nia ahh.. xD di yan tatanggapin ni sir

Answer 13

panu kasi derek

Answer 14

hahaha. magtanung ka ulit sa ibang tao.. i-bump mo ulit ung post

Answer 15

I NEED SOLUTION FOR A HIGH SCHOOL STUDENT

Answer 16

pls pls answer