how do you solve for a right triangle if the |dw:1340804706494:dw|
Trying to get your sketch to display... |dw:1340804706494:dw|
Huh? That's odd your sketch didn't display even when I copied it over to my post
Try sketching again, something went squirrely here.
yeah uiim confused i was trying to draw it out but its a right triangle ABC if A=16 degrees, c=14, and C=90 degrees
|dw:1340805162225:dw|
@agentx5 i think it worked now
\(\angle A = 16^o\) , \(\angle C = 90^o\) isn't what you drew there... At the minimum it should appear like this, where the "square corner" symbol means by definition, 90 degrees. |dw:1340805661544:dw| \[\huge \triangle = 180^o = \angle A + \angle B + \angle C \] You should be able to find B. Then it's just a matter of SOH-CAH-TOA and your trigonometric functions (sine, cosine, tangent). :-)
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