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Solve S = 4v2 for v. Solve M = 2x + 3y for y.
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ok for S you can just isolate the v would you would divide both by 4 to make S/4 = v^2. then square root to get rid of the square of the v = \[\sqrt{S/4}\]
to solve for y you kind of do the same thing and isolate the y. do this by minus the 2x from both sides to give M-2x = 3y then divide 3 by both sides. with this you get \[M/3 - 2x/3 = y\]
ok thank you . so does that mean that what you wrote is the solution?
yes. to both of them. and how to solve them in case you run up on another one you can do it for yoruself
ok :) thank you
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