What is the remainder of (x^3 – 6x – 9x + 3) ÷ (x - 3)
is this long division calculus?
No algebra 1
ok same concept though, one sec
write up x-3 divided by x^3 - 6x - 9x +3 as in long division on yoru paper.
ok I still dont get it tho
ok well what you do is just like in long division you write something on the top and multiply it into x-3 to get something to subtract from the big one so.....
first off, theres no x^2 in this, just 6x and 9x ?
is the problem at first written correctly is what i'm asking
yeah
ok give me a sec
ok thank you
ok, x goes into x^3 an amoutn of times of x^2 so you would write x^2 in the top. and the numbers you minus from the big number ends up being x^3 - 3x^2.
first simplify this from -6x -9x to -15x if thats how it is
ok thank u
ok then what do you end up with after minusing x^3 - 3x^2 from the equation?
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