What is the remainder of (x^3 – 6x – 9x + 3) ÷ (x - 3)
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OpenStudy (anonymous):
is this long division calculus?
OpenStudy (anonymous):
No algebra 1
OpenStudy (anonymous):
ok same concept though, one sec
OpenStudy (anonymous):
write up x-3 divided by x^3 - 6x - 9x +3 as in long division on yoru paper.
OpenStudy (anonymous):
ok I still dont get it tho
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OpenStudy (anonymous):
ok well what you do is just like in long division you write something on the top and multiply it into x-3 to get something to subtract from the big one so.....
OpenStudy (anonymous):
first off, theres no x^2 in this, just 6x and 9x ?
OpenStudy (anonymous):
is the problem at first written correctly is what i'm asking
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
ok give me a sec
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OpenStudy (anonymous):
ok thank you
OpenStudy (anonymous):
ok, x goes into x^3 an amoutn of times of x^2 so you would write x^2 in the top. and the numbers you minus from the big number ends up being x^3 - 3x^2.
OpenStudy (anonymous):
first simplify this from -6x -9x to -15x if thats how it is
OpenStudy (anonymous):
ok thank u
OpenStudy (anonymous):
ok then what do you end up with after minusing x^3 - 3x^2 from the equation?