solve the following trigonometric equation:
3sin^(2)x=cos^(2); where x is greater than or equal to 0 and less than 2 pi

Question

solve the following trigonometric equation:
3sin^(2)x=cos^(2);  where x is greater than or equal to 0 and less than 2 pi

myininaya · Answer

Put everything on one side and write in terms of one trig function

myininaya · Answer

You will need the identity 
$$\cos^2(x)=1-\sin^2(x)$$

anonymous · Answer

is it asking for an actual number?

myininaya · Answer

Yes we are looking for values of x that satisfy that equation 
I think you are missing an x
$$3 \sin^2(x)=\cos^2(x) $$ 
right?

anonymous · Answer

Oops! Yes, I was missing an x. So you place everything on one side and set it equal to 0?

myininaya · Answer

yes

myininaya · Answer

Also write in terms of one trig function

anonymous · Answer

Wait, would you set it equal to zero or one? Because if it is equal to zero then how do I use the identities?

myininaya · Answer

I said put everything on one side.
How do you do that?
Subtract cos^2(x) on both sides
And then use the identity I gave you above
Write what you get after you have follow these instructions
No about the equals to 1. That wouldn't help (adding a 1 on both sides would not help)

anonymous · Answer

I got the answer. Thanks