Need help with checking why my answer is wrong with this midpoint rule calculation for the following integral:
$$\large 4 \int\limits_{1}^{5} \frac{\cos(4x)}{x} dx$$
n = 8 (number of samples)
Thus: $\triangle$x = 1/2 or 0.5

Question

Need help with checking why my answer is wrong with this midpoint rule calculation for the following integral:
$$\large 4 \int\limits_{1}^{5} \frac{\cos(4x)}{x}  dx$$  
n = 8  (number of samples)
Thus: $\triangle$x = 1/2 or 0.5

anonymous · Answer

I am getting 0.4679580589

anonymous · Answer

^  See scratch work there.   Something is messing up here because I didn't have an issue with the Trapezoid Rule version.

anonymous · Answer

Noticed I was missing one cos(4*4.75)/4.75 as cos(4.75)/4.75 by mistake and now it is 0.474429 to six significant figures, but still not being accepted as the correct answer.