Question

I understand how to solve now. But how would I used a calculator to do all of that? haha

Answer 1

f'(x)=3x^2+4x-8
Set that equal to 0 and solve for x:
3x^2+4x-8=0, x=-2.431, or x=1.097

Answer 2

oh okay [:

Answer 3

b) Find the 2nd derivative: 6x+4
Plug in x=-2.431:
6*(-2.431)+4<0, so x=-2.431 is a max

Answer 4

Plug in x=1.097
6*1.097+4>0, so x=1.097 is a min

Answer 5

I think the function in the problem is f'(x), not f(x).

Answer 6

Thanks a bunch, I'll review this.