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Find f(2) and f(a + h) when f(x) = 3x^2 + 2x + 4 f(2)= 3(2)^2+2(2)+4 = 20 but i dont get the f(a+h) f(a+h)= 3(a+h)^2+2(a+h)+4 right?
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subtitution f=2 and f=(a+h)
f(2)= 3(2)^2+2(2)+4 f(a+h)=3(a+h)^2+2(a+h)+4 you can solve from here
@Nancy_Lam i already did f(2) i need help with simplifying the second one: 3(a+h)^2+2(a+h)+4
3(a+h)^2+2(a+h)+4 is easy to solve
3a+3h^2+2a+2h+4?
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[3*(a+h)(a+h)] + [2a+2h] + 4 [3*( a^2+2ah+h^2)] + 2a+ 2h +4 can you solve from here?
is it 3a^2+2ah+2a+h^2+2h+4?
= 3a^2+3h^2+6ah+2a+2h+4
oh ok thank you! :)
nedal?
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