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The point A(-3, -2) is translated using T: (x,y) → (x + 5, y - 3). What is the distance from A to A'?
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x coordinate is moved to the right 5 units that is why it is x+5 the y coordinate is moved down 3 units, that is why it is y-3
because its moving down
point is moved 5 units to the right and 3 down
A' coordinates are (2,-5).Distance between A and A' is \[\sqrt{((2-(-3))^2+((-5-(-2))^2}=\sqrt{34}\]
Why not A) calculate A and A', then apply distance formula or B) apply distance formula to two general points, then plug in for \(x\) and \(y\)?
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@burakb, we do not give full answers here. See the Code of Conduct.
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