Create a quadratic equation and demonstrate how it would be solved by graphing, factoring, the quadratic formula, and by completing the square.
Well can you create one for us?
First off do you know what a quadratic equation looks like?
I wouldn't know where to start...
not right off the bat but I have been studying it.
can you help me on the first to , I have an Idea on squaring but the other two not really.
\[ax^2 + bx + c = 0\]
okay.
That's how a general quadratic equation looks like. Where a b and c are any values
a usually equals 1 to make it easier to solve
so I just have to fill thos in with #'s??
Well like I said a is 1 to make it easier to solve. Then b and c have some connection to each other in order to use the complete square method
so like 2 and 4?
Well it's more complicated than that
For example (x + 2) ( x+2)
give you x^2 + 2x + 2x + 4= x^2 +4x+4
yah, but that's after factoring right?
in this case b=4 and c=4
Yeah
oh okay.
But I'm talking about completing the square.
yah, I got the hang of it now. But what about the quadratic factoring.
It's hard for me to explain that part but try other example like (x+2)(x+1)
To see what b and c equal
uh-huh.
(x+2)(x+1)= x^2 + 2x + x + 2= x^2 + 3x + 2
in that case b=3 and c=2
are we still talking about completing the square?
yeah
okay.
Lets say a=1 b=4 c=4 what's the general equation look like?
it's going to be this equation ax^2 + bx + c = 0? or is this for somthing else?
Yeah exactly like that
so all these examples that you just did can be pluged in for that?
and that's jusr for completing the aquare or general form now?
No you can solve using quadratic formula for example \[\begin{array}{*{20}c} {x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} & {{\rm{when}}} & {ax^2 + bx + c = 0} \\ \end{array} \]
You plug in a b and c to the left and solve for x
ah, okay.
\[\pm \] this sign means you have to do it two times. Solve it once for + and another one for - so you should get two answers.
for x
For the example that I gave you where a=1 b=2 c=2 you get one answer for x
because it's a special case.
okay I get all that now. But the reason way I asked this question is becaues I don't know how to set it up. like I dnt know which numbers to chose at the begining. That why I wanted some one to set up all three and now thanks to you I can do the rest.
The thing is sometimes I have trouble too knowing how to set it up and Ive been taking math for a while now. Some people can see it really fast and some people can't. I can't so what I do is try to set up a complete square first. (x+2)(x+1) then I simplify it (x+2)(x+1)= x^2 + 3x + 2 then I see what a b and c equal
That's how I get the general form of the equation. And if they tell me to complete the square I work backwards again.
x^2 + 3x + 2=0 Complete the square Oh ok I can do it now It's (x+2)(x+1)
(x+2)(x+1)=0 See how I did it.
yah, I saw :)
at least I know how to do that now.
Cool I can do it faster now because I practice them a lot so if you keep doing it then sooner or later you will be able to catch them really fast.
Good Luck.
thanks , btw ur a gud teacher ;)
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