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OpenStudy (anonymous):
The derivative of h(x) is given by the function h '(x) = x + 2cosx. Use your calculator to determine the number of times the graph of h(x) changes concavity on the interval [0, ]. Justify your answer using a complete sentence.
14 years ago
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OpenStudy (anonymous):
[0,4PI]
14 years ago
OpenStudy (anonymous):
derive it two times and do it equal zero
14 years ago
OpenStudy (anonymous):
= 1 - 2sin(X)
14 years ago
OpenStudy (anonymous):
dont get the second part
14 years ago
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OpenStudy (anonymous):
w8 nvm is it 2?
14 years ago
OpenStudy (anonymous):
concavity is tested by y'' test
14 years ago
OpenStudy (anonymous):
0=1-2sin(x)
-1=-2sin(x)
1/2=sin(x)
14 years ago
OpenStudy (anonymous):
happens at pi/6
14 years ago
OpenStudy (anonymous):
only once?
14 years ago
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OpenStudy (anonymous):
nope it says in the interval of 0 to 4pi
14 years ago
OpenStudy (anonymous):
so two revolutions
14 years ago
OpenStudy (anonymous):
ok
14 years ago
OpenStudy (anonymous):
so it's pi/6, 5pi/6, 13pi/6, 17pi/6
14 years ago
OpenStudy (anonymous):
using a calculator if you look at the graph
14 years ago
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OpenStudy (anonymous):
k thanks
14 years ago
OpenStudy (anonymous):
what do you mean by 2 revolutions?
14 years ago
OpenStudy (anonymous):
2 revolutions around the unit circle
14 years ago
OpenStudy (anonymous):
4pi =720 degrees
14 years ago
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OpenStudy (anonymous):
alright
14 years ago
OpenStudy (anonymous):
thanks again
14 years ago
OpenStudy (anonymous):
no problm
14 years ago
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