The derivative of h(x) is given by the function h '(x) = x + 2cosx. Use your calculator to determine the number of times the graph of h(x) changes concavity on the interval [0, ]. Justify your answer using a complete sentence.
[0,4PI]
derive it two times and do it equal zero
= 1 - 2sin(X)
dont get the second part
w8 nvm is it 2?
concavity is tested by y'' test
0=1-2sin(x) -1=-2sin(x) 1/2=sin(x)
happens at pi/6
only once?
nope it says in the interval of 0 to 4pi
so two revolutions
ok
so it's pi/6, 5pi/6, 13pi/6, 17pi/6
using a calculator if you look at the graph
k thanks
what do you mean by 2 revolutions?
you'd have to integrate up one to actually see the graph of the function but the inflection points http://www.wolframalpha.com/input/?i=x%5E2%2F2%2B+2*sinx+from+0+to+4pi you can see at certain points it switches from concave up to concave down
2 revolutions around the unit circle
4pi =720 degrees
alright
thanks again
no problm
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