just a question. when finding the nth term of a geometric sequence as a function of x , is it possible to have multiple answers nth term functions that are valid?
sorry correction.. * as a function of n...
Formula to find nth term is: \[\huge t_n = a.r^{n-1}\]
Since n can take only one value at a time so you will have only one particular value...
yes agreed but for a particular geometric sequence, can Tn vary is what im asking
Tn is the last term.. It depends on how we choose the last term.. We will get the last term by putting different values of n..
okay i dont think your understanding me... let me give you an example... the geometric sequence as such. : 6, -9, 27/2, -81/4, 243/8....... i found that the nth term could possibly be \[A_n= 6(-3/2)^{n-1}\] but the nth term could also possibly be :\[A _{n}=-4(-3/2)^{n}\] what im asking is if this is possible to have two different types of equations for the nth term or is one of them incorrect?
How you got the second one?
But their answer will be same..
You did nothing but you solve the equation further..
well i actually didnt get the second one.... this question comes from my textbook... i came up with the first one but the answer in my textbook is the second one.... i tested the 1st 1.. (the one i made) and it works but so does the one from the text book so is it possible for both to be correct or is the one i came up with incorrect?
See, \[\huge t_n = a.r^{n-1}\] \[\huge t_n = \frac{a.}{r}r^n\]
See, both the equations are same. You can write 4 as: 4*1 or you can write it as 2*2 Just the same thing..
but is the first one correct then?
Yes dear first one is the actual formula and the second one is derived from first by just solving it..
okay so they are both in simplified form?
See first one is a standard formula and the second one is just derived from that formula..
Both are the one and the same thing...
okay thank you:)
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