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What happens to the area of the circle if its radius is doubled?
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It is similar to your previous question. You can try it yourself. Take radius as x and 2x. And apply the formula and take ratio.
Like I said earlier, radius is the length IF \(k\) is doubled, \(2k\) would be your new length. Area would become \((2k)^2=4k^2\)
Now you can compare it would your old area, which is \(k^2\) \(4k^2 \div k^2= ~?\)
you mean to say that area also gets doubled?
Re-read my post above
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4
Yes
area gets four times!
yup
got it! thank you
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You are welcome :)
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