I don't know how to do this equation.. (5x^2 + x – 4)(x + 2)
Make the factors of first parenthesis.. See tell me the two numbers with sum = 1 and product = -20??
I don't know how to do that.
See, try with 4 and 5.. we need -20.. in what way I multiply 4 and 5 to get -20?
Negative + positive?
Which one should be negative and which one should be positive?
It doesn't matter. Either one works.. (-4)(5)=-20 and (-5)(4)=-20
But if I say that their sum should be 1 then which sign you will apply to which?
I don't know.
See, you told we can take -4 and 5 or -5 and 4 just add them to get 1. which will it adds up to 1? -5 + 4 Or, -4 + 5 ??
-4+5
Yes now you got it.. or if I multiply x to both -4 and 5 what you get?? x(-4 + 5) distribute x inside..
-4x+5x
Yes so you agree? 1x = (-4 + 5)x ??
Yes.
Now tell me the expression in first parenthesis?
Um.. what expression?
See in the question what is the expression in first bracket? it is quadratic for which we are solving for..
5x^2 ?
tell me the whole..
5x^2 + x - 4
Yes.. now I make you agree that 1x = (5 - 4)x Yes or not?
Is x = (5-4)x right??
Yes?
Then replace the middle term of the expression: 5x^2 + x - 20 Here you can replace middle term x with (5-4)x can you do it?
5x^2 + (5-4) - 20 But how did you replace the - 4 with the 20?
no no.. See we are to replace middle term only using the two numbers we got.. See: \[5x^2 + x -20 = 5x^2 + 5x - 4x -20\] This step are you getting?? I just repace x by (5-4)x and then distribute x to get 5x - 4x Getting or not?
Yes, I understand.
Now take common that can you take out..
See: from: \[5x^2 + 5x\] What can be taken out of it as common?
The 5x?
Yes.. so you have: \[5x(x + 1) -4x - 20\] Now from the next part what can be taken out?
How did you get 5x(x+1)-4-20 ?
After taking 5x as common tell me what you are left with?
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