Question

Circle S has an equation of (x – 16)2 + (y + 9)2 = 4. What is the center and radius of circle S?

Center: (16, -9); Radius: 4

Center: (-16, 9); Radius: 2

Center: (16, -9); Radius: 2

Center: (-16, 9); Radius: 4

Answer 1

\[\small\text{Form of a Circle: } (x - h)^{2} + (y - k)^{2} = r^{2} \text{where the center is (-h, -k) and the radius is r.}\]

Answer 2

ok

Answer 3

so what is the answer cause i don't understand

Answer 4

Alright. h = -16 and k = 9. WHat is (-h, -k) given the values?

Answer 5

can you explain?

Answer 6

Alright. If you have h = -16,, then -h = -(-16) and -h = 16.
Do you understand that?

Answer 7

yes

Answer 8

ALright. Given that, if k = 9, then -k = ?

Answer 9

-9?

Answer 10

Yup. Therefore, the center is (16, -9).
Now, for the radius, r = radius.
\[r^{2} = 4\]\[\sqrt{r^{2}} = \sqrt{4}\]THerefore, r = ?

Answer 11

16,-9?

Answer 12

(16, -9) is the CENTER.
What is the value of √4?

Answer 13

2

Answer 14

ok. THat means that the radius is 2.
THerefore, the center is (16, -9) and the radius is 2.

Answer 15

oh ok thank you

Answer 16

np :)