Question

Simplify the sum.

(2u3 + 6u2 + 3) + (2u3 – 7u + 6)
A. 9 – 7u + 6u2 + 4u3

B. 0u3 + 6u2 – 7u + 9

C. 0u3 – 7u2 + 6u – 9

D. 4u3 + 6u2 – 7u + 9

Answer 1

\[\huge (2u^3 + 6u^2 + 3) + (2u^3 - 7u + 6)\]
\[\huge \implies 2u^3 + 6u^2 + 3 + 2u^3 - 7u + 6\]
may i ask where you're getting confused?

Answer 2

D

Answer 3

don't understand it

Answer 4

do you understand my step so far? i just removed the parenthesis

Answer 5

yes

Answer 6

then what do you do?

Answer 7

then you combine the like terms
\[\LARGE \implies (2u^3 + 2u^3) + (6u^2) + (-7u) + (3 + 6)\]
there are no other u or u^2 so you cant combine them..but there are two u^3 and two constants..so you can combine those

got it?

Answer 8

yes now what?

Answer 9

you combine..what is 2u^3 + 2u^3?

Answer 10

4u^3

Answer 11

and what's 3 + 6?

Answer 12

9

Answer 13

therefore you have \[\huge 4u^3 + 6u^2 - 7u + 9\]

Answer 14

how did you get minus 7u

Answer 15

thanks for the help might need more soon don't really understand this stuff

Answer 16

do you get where -7u come from now?

Answer 17

yes

Answer 18

great :D

Answer 19

D. 4u3 + 6u2 – 7u + 9
I got this correct on my test.