Question

#1
Using long division, divide:

P(x)= 2x^3- 3x^2-2x
D(x)= 2x-3


ALSO: Heres another one :)
#2

P(x)= x^4 - x^3 + 4x + 2
D(x)= x^2 +3

Answer 1

I'll do #1 and you try #2
For #1
x^2 -1
--------------------
2x - 3 ) 2x^3 - 3x^2 - 2x + 0
2x^3 - 3x^2
-------------------
- 2x + 0
- 2x + 3
-------
- 3

Answer 2

I've tried #2 many times my problem is:
I get x^2 from the first dividing x^4 by x^2 then multiply that to x^2 +3 then put that underneath and add. I get -x^4 and +3x^2 which there is a gap space between powers 4 to 2 the 3 space is missing :

x^4 -X^3 +0x^2
-x^4 + 3x^2 <(This is what i'm adding)
Do you understand what I mean I dont understand what you are supposed to do there, when there is a space.

Answer 3

Thanks for the first one, I got confused after canceling the first two, I thought that was the end, now I know to bring down the other two remaining...

Answer 4

Can you show your steps like I did for #1?

Answer 5

okay!
One second

Answer 6

x^2
___________________________
x^2 + 3 ( x^4 -x^3 + 0x^2 + 4x +2
-x^4 -3x^2
-----------------
^

Basically how do I continue, I don't understand when there is a space.

Answer 7

x^2
___________________________
x^2 + 3 ) x^4 -x^3 + 0x^2 + 4x +2
x^4 3x^2
------------------------
- x^3 - 3x^3
Got it?

Answer 8

Okay so bring down -x^3 and continue okay ill try it now.

Answer 9

Do you divide the -x^3 by x^2 still?

Answer 10

You may say so....
But my way of doing it is 'what times x^2 gives -x^3'..
In this case, it's -x

Answer 11

I'm still getting caught up in steps beyond that one

Answer 12

Perhaps you can see if you understand my workings for #1. This may help a bit...

Answer 13

yeah okay thanks