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evaluate log2 16 the 2 is small...
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\[\log_{2} 16\]
your job is to find \(y\) if \(2^y=16\)
y=4?
\[\log_b(x)=y\iff b^y=x\] and so \[\log_2(16)=y\iff 2^y=16\] in other words your job is to find what number you would raise 2 to in order to get 16 yes it is 4 because \(2^4=16\)
so \[\log_{5} 125\] is y=3...?
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you got it~
so \(\log_5(125)=3\) logs are exponents, if you can switch back and forth between logarithmic and exponential forms quickly this will not be too hard
gotcha!! now what about ln\[1/e^{5} \]
ln in front of the problem
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