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Find the integral 1 ---- x(ln(x))^6
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I guess we could start out with \[x^-1 * (\ln(x))^{-6}\]
better: \[\ln(x)^{-6}/x\] and solve by substitution
or actually keep it as 1/x for the du
u = ln(x) du = 1/x dx
yes
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so it's going ot be u^-6 du
nice! :D
\[\frac{u^{-5}}{5} + c?\]
\[\frac{(\ln(x))^{-5}}{5} + c?\]
don't forget - sign
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\[-\frac{(\ln(x))^{-5}}{5} + c?\]
yes
Been doing stupid stuff like that all day... Have the worst headache :(
:)
:D
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