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Frank kicks a soccer ball off the ground and in the air with an initial velocity of 30 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?
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Maximum height occurs where H '(t) = 0 and H ''(t) < 0. H(t) = -16t^2 + 30t + 0 H '(t) = -32t + 30 0 = -32t + 30 t = 30/32 = 15/16 H ''(t) = -32 < 0 so H(15/16) is a maximum. H(15/16) = -16(15/16)^2 + 30(15/16) + 0 = -225/16 + 450/16 = 225/16 feet
@doubledrive u copy and paste this from yahoo answers didn't u -.-
did it help u??
yeah
thx
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lol, ur welcoke
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