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Mathematics 15 Online
OpenStudy (anonymous):

I need help with my math assignment pleasseeeee

OpenStudy (anonymous):

OpenStudy (anonymous):

where is it?

OpenStudy (anonymous):

its the file attached.

OpenStudy (anonymous):

That's an entire assignment! No one is going to help you unless you post the questions individually ;)

OpenStudy (anonymous):

AAS As 2 next angles and sides corresponding equal!

OpenStudy (anonymous):

then answer one

OpenStudy (anonymous):

:) It'll be easier for us to click on the image, so next time save as pic then post it!

OpenStudy (anonymous):

ohp :3

OpenStudy (anonymous):

Number 1 is AAS... Lol

OpenStudy (anonymous):

Yea I got that :3

OpenStudy (anonymous):

Number 4 is "angle B is congruent to angle E" Sorry I'm skipping around the questions ahaha :P

OpenStudy (anonymous):

Thank you and that's ok just do what you can :3

OpenStudy (zepp):

Alright, for question 2, let me rewrite the whole thing here

OpenStudy (anonymous):

@mellieinc Sorry, most of the symbols aren't showing up on my computer for some reason D:

OpenStudy (anonymous):

awww :(

OpenStudy (zepp):

Good, now let's go step by step;

OpenStudy (zepp):

This student first said: since AB=2 and DF=2, then AB must be congruent to DF, by the transitive property, right?

OpenStudy (anonymous):

siiiii :3

OpenStudy (zepp):

So line 1, correct;

OpenStudy (zepp):

Line 2 states that angle A congruent to angle F, which are both 63 degrees, therefore, line 2 is also correct. Do you agree?

OpenStudy (zepp):

Great, now 3rd line is written to find the length of AC A is at (1,2) C is at (3,3) They used the distance formula which is \[ d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] In our case, \(x_1=1;~~y_1=2\) (Point A) and \(x_2=3;~~y_2=3\) (Point C) Not too confusing here?

OpenStudy (anonymous):

nope

OpenStudy (zepp):

Alright, now plug all value in the formula and let's solve; \[ d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] \(x_1=1;~~y_1=2\) (Point A) \(x_2=3;~~y_2=3\) (Point C) NOTE: It could be \(x_1=3;~~y_1=3\) (Point C) \(x_2=1;~~y_2=2\) (Point A) Like this, too. \[ d=\sqrt{(1-3)^2+(2-3)^2}\] Does that look like what he has?

OpenStudy (anonymous):

so line 3 is equal?

OpenStudy (zepp):

So what I just wrote above correspond to what he wrote, exact?

OpenStudy (anonymous):

yes

OpenStudy (zepp):

Good, so line 3 has no mistake, let's move to 4.

OpenStudy (anonymous):

yayyy

OpenStudy (zepp):

Following the same process, we have to find the length EF: \(x_1=5;~~y_1=3\) (Point F) \(x_2=3;~~y_2=2\) (Point E) \[d=\sqrt{(3-5)^2+(2-3)^2}\] Does that correspond to what he wrote?

OpenStudy (zepp):

Actually, this has no mistake, unless they are very meticulous and want the angle to be in the middle, so \(\Delta \text{BAC}\cong\Delta \text{EFD}\)... @AccessDenied

OpenStudy (anonymous):

so its line 6?

OpenStudy (zepp):

Yeah, only thing I can find, need someone to check though. @KingGeorge @inkyvoyd

OpenStudy (anonymous):

so line six is forsure the answer because the others are correct

OpenStudy (zepp):

Yeah, if we proceed by elimination, 6 would be the only option left

OpenStudy (anonymous):

true

OpenStudy (zepp):

Ok, number 3 now. :)

OpenStudy (anonymous):

yayyyy :)

OpenStudy (zepp):

|dw:1341354074718:dw| Given these two triangles are congruent, tell me about your understanding of 'congruent triangles' and their properties? :)

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