Question

In your own words explain why a quadratic
equation can't have one imaginary solution.

Answer 1

because according to the discriminant of the quadratic formula...
\[b^2 - 4ac > 0 \rightarrow \text{2 real solutions}\]
\[b^2 - 4ac = 0 \rightarrow \text{1 real solution}\]
\[b^2 - 4ac < 0 \rightarrow \text{2 imaginary solutions}\]
does that answer your wonders? :)

Answer 2

Yes, but do you know exactly why?

Answer 3

Or are those just postulates?

Answer 4

lol wow my 1000th medals for answers hehe

and what do you mean "exactly why"

Answer 5

Wouldn't it simply be because the formula includes: \[\pm \sqrt{b^2-4ac}\]So for any root that contains an imaginary value would have two solutions.

Answer 6

Ooooooh yes the plus and minus sign

Answer 7

Thanks, I wish i could give you a medal lol

Answer 8

:)

Answer 9

Sorry :\

Answer 10

I won't lose any sleep over it :P

Answer 11

@wowigetit it's actually because of the square root not the plus minus ;)

Answer 12

Well, if it weren't for the plus/minus, you could actually get *one* imaginary solution :)

Answer 13

oh you mean the positive and negative values huh