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Mathematics 24 Online
OpenStudy (anonymous):

What are inflection points and how do you find them?

OpenStudy (lgbasallote):

i believe you take the second derivative. when there is a sudden change from + to - then there is an inflection point...i believe this happens in cubic functions

OpenStudy (lgbasallote):

does that help? :)

OpenStudy (anonymous):

1) Set the second derivative equal to zero 2) Solve for x and those give you the inflection points

OpenStudy (anonymous):

Inflection points are found by finding the zeros of the second derivative. f(x) = x^3 -12x f'(x) = 3x^2 -12 f''(x) = 6x Set f''(x) = 0 6x = 0 x = 0 In order for x = 0 to be an inflection point, f''(x) must change signs. When x < 0, then f''(x) < 0 (You can find this out by testing a number less than 0 in the second derivative). When x > 0, then f''(x) > 0 (again you can use a test point to find this out). Since f''(x) changes signs at x = 0, then that is an inflection point. To find the second coordinate of the point, simply plug in x=0 into f(x). f(0) = (0)^3 -12(0) = 0 - 0 = 0 So the inflection point is (0,0). now,u can depend on it on how to solve,,this is an example :)

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