Question

Need help. Step by step. Find the differential equation of all circles tangent to the x-axis.

Answer 1

@anusha.p . After knowing (x-a)^2 + (y-b)^2 = b^2, what's next? Differentiate? Thanks

Answer 2

Differentiating wrt x will give:
2(x-a)+2(y-b)y' = 0
(x-a)+(y-b)y"=0

Then, how to differentiate wrt y?

Answer 3

The answer is supposed to be like this: [1+(y')^2]^3= [yy''+(y')^2]^2.
Will it look something like that?

Answer 4

i did it but i get [1+(y')^2]^3= [1+yy''+(y')^2]^2
i dont know why
let me check it again

Answer 5

i think my answer is correct let me show my work
give me a sec

Answer 6

ok

Answer 7

here

Answer 8

@mukushla thanks! i get it now,,can i ask one more problem?

Answer 9

yes. but if it is math plz post it in math category.
tnx

Answer 10

how about find the differential equation of all straight lines unit distance from the origin.

Answer 11

@mukushla