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write the equation in the form axsquared+bx+c=0: (2/x)squared-4=7
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\[(\frac{2}{x})^2 - 4 = 7\] \[\frac{4}{x^2} - 4 - 7 = 0\] \[\frac{4}{x^2} - 11 = 0\] \[4 - 11x^2 = 0\] got that?
actually you have to rearrange it \[-11x^2 + 4 = 0\] \[11x^2 - 4 = 0\] so any unclear steps?
but...it has no b..., there is just the a=11 & the c=-4
yup b = 0
ah...... ok its clear 2 me now
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tnx alot
great! that's nice to hear :)
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