Question

Write the equation of the line which passes through (–4, 2) and is parallel to y = –x + 6 in slope-intercept form.

Answer 1

you have the line
\[ y=-x+6 \]
what is the slope?

Answer 2

-1/0 I think

Answer 3

no!
the slope is the coeficient of x!

Answer 4

the required line is parallel to y=-x
so it has the same slope with y-=-x
slope =-1
(y-2)/(x-(-4)) = -1
y-2=-(x+4)
y-2=-x-4
y=-x-2

Answer 5

Umm.....The slope is -1 !

Answer 6

slope is y/x
y=-x
y/x=-1
so the slope is -1

Answer 7

yes!
so you already have m=-1 and the point
\[ (x_0,y_0)=(-4,2) \]
the equation you are looking for is
\[ y-y_0=m(x-x_0) \]
so what do you get?

Answer 8

y-2=x-(-4)

Answer 9

what about m=-1?

Answer 10

y-2=-1x-(-4)

Answer 11

you have paretheses missing!

Answer 12

y-2=-1(x-(-4)

Answer 13

that is right
\[ y-2=(-1)(x-(-4))=-x-4 \]

Answer 14

Ok Thanks !

Answer 15

you are welcome

remeber!
to determine the equation of a line you need
(i) two points (from which you can compute the slope), or
(ii) the slope and one point