Question

Solve for u.

(-3/4u+12)+2=(-3/u+3)

Answer 1

start with multiplying 4u through out

Answer 2

Is the problem \[-\frac{3}{4u + 12} + 2 = -\frac{3}{x + 3}?\]

Answer 3

yes

Answer 4

Oh wait no. there is no x in the problem

Answer 5

\[-\frac{3}{4u + 12} + 2 = -\frac{3}{u + 3}\]\[-\frac{3}{4(u + 3)} + 2 = -\frac{3}{u + 3}\]\[-\frac{3}{4(u + 3)} + (2 \times \frac{4(u + 3)}{4(u + 3)}) = (-\frac{3}{u + 3} \times \frac 44)\]Can you solve from here?

Answer 6

no i still need help

Answer 7

\[-\frac{3}{4(u + 3)} + (2 \times \frac{4(u + 3)}{4(u + 3)}) = (-\frac{3}{u + 3} \times \frac 44)\]\[-\frac{3}{4(u + 3)} + \frac{8(u + 3)}{4(u + 3)} = -\frac{12}{4(u + 3)}\]Drop the denominators.\[-3 + 8(u + 3) = -12\]Now can you solve?

Answer 8

yes thank you

Answer 9

np :)