Ask your own question, for FREE!
Mathematics 27 Online
OpenStudy (anonymous):

What is the equation of the line parallel to the graph of y = 5x -3 and through the origin?

OpenStudy (anonymous):

This is in slope-intercept form, which makes it easier to solve. \[y=mx+b\] Where b is the y intercept, in the question, the case would be -3, if there was no b, what would the y intercept be? To find a parallel line to another line on a graph, it must have the same slope, where a perpendicular line must have a slope which is the reciprocal of the original. For example, 1/3 would be a slope perpendicular to your line. But since it is parallel, we use the same slope. Can you solve it?

OpenStudy (anonymous):

y = 5x - 3

OpenStudy (anonymous):

Your slope is right, but the -3 means it's the same line, which is not parallel, and does not cross the origin. (0,0) is the origin of a graph. For your original equation the line crosses (0,-3), but you want it to cross (0,0). So take just y = 5x to find your parallel line that crosses the origin.

OpenStudy (anonymous):

oh ok i get it thanks

OpenStudy (anonymous):

Yup :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
EdwinJsHispanic: another singing vid, please give me your thoughts on it
21 seconds ago 2 Replies 0 Medals
SwaggyMark: Need help on process of annuity problem
20 hours ago 3 Replies 0 Medals
SwaggyMark: Need guidance on how to solve this annuity problem
20 hours ago 25 Replies 1 Medal
Nina001: Tips for acid reflux
20 hours ago 3 Replies 0 Medals
gelphielvr: How would you write Dinitrogen disulfide?
1 day ago 3 Replies 1 Medal
xXAikoXx: What's ethos, pathos, logos?
1 day ago 9 Replies 4 Medals
Breathless: Sonic. Dead or alive. IS MINE
17 hours ago 6 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!