What is the simplified form of the expression the square root of the quantity 4 times c to the sixteenth power. - the square root of c squared. + 6the square root of c squared. + the square root of the quantity 9 times c squared.?

Question

campbell_st · Answer

$$\sqrt{4c^{16}} - \sqrt{c^2} + 6\sqrt{c} + 9\sqrt{c^2}$$

simplify the radicals

$$\sqrt{4c^{16}} = 2c^8$$
$$\sqrt{c^2} = c$$
$$9\sqrt{c^2} = 9c$$

make the substitution and simplify

anonymous · Answer

can you explain further please?

campbell_st · Answer

ok so after substituting 

$$2c - c + 6\sqrt{c} + 9c = (2c - c + 9c) + 6\sqrt{c}$$

just simplify the part in brackets

anonymous · Answer

2c+9c

anonymous · Answer

right?