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can somebody help me with an integral ill post it
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\[\int\limits_{}^{}x^3\div \sqrt{4+x^2} dx\]
Have you tried the substitution u = x^2+4?
yeah du would just be 2xdx and it wouldnt work
why? You're left with x^2, which is just u-4. So we have (u-4)/sqrt(u) du.
the derivative of x^2+4 is 2xdx not x^2dx so that wouldnt work
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