find the limit limit as x approaches infinity of (7/n) + 1
n approaches to infinity, right?
what happens as you divide 7 by a bigger, bigger, bigger number and then add 1? Try dividing 7 by 5000 and then add 1. What value are you getting close to?
yes sorry n
infinity?
7/infinity =0 (as the larger the denominator, the smaller the value of the fraction is) so limit as n approaches infinity of (7/n) + 1 =1
\[\frac{7}{5000}+1=1.0014\] and well, 5000 is much smaller than infinity, so as you grow the denominator, the amount of zeros will grow in the decimal taking you closer to 1.
so 1?
yes
THANKS!
what about (7+n)/n
Its the same..
it is?
(7+n)/n = 7/n +n/n = 7/n +1 this is the same as the previous question
sorry i meant (7+n)/n^2
answer is 0
and (7+n^2)/n
the answer is not defined...
the choices are : a)0 b)1 c)postive infinty
positive infinity
\[\lim_{n \rightarrow \infty} \frac{7+n^2}{n}=\lim_{n \rightarrow \infty} \frac{7}{n}+\frac{n^2}{n}\]
the 7/n goes to 0 and the n^2/n goes to infinity. so answer is infinity
MUCH THANKS!!!!!
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