Question

find the limit

limit as x approaches infinity of (7/n) + 1

Answer 1

n approaches to infinity, right?

Answer 2

what happens as you divide 7 by a bigger, bigger, bigger number and then add 1?

Try dividing 7 by 5000 and then add 1. What value are you getting close to?

Answer 3

yes sorry n

Answer 4

infinity?

Answer 5

7/infinity =0 (as the larger the denominator, the smaller the value of the fraction is)
so
limit as n approaches infinity of (7/n) + 1 =1

Answer 6

\[\frac{7}{5000}+1=1.0014\]
and well, 5000 is much smaller than infinity, so as you grow the denominator, the amount of zeros will grow in the decimal taking you closer to 1.

Answer 7

so 1?

Answer 8

yes

Answer 9

THANKS!

Answer 10

what about (7+n)/n

Answer 11

Its the same..

Answer 12

it is?

Answer 13

(7+n)/n = 7/n +n/n = 7/n +1
this is the same as the previous question

Answer 14

sorry i meant (7+n)/n^2

Answer 15

answer is 0

Answer 16

and (7+n^2)/n

Answer 17

the answer is not defined...

Answer 18

the choices are :
a)0
b)1
c)postive infinty

Answer 19

positive infinity

Answer 20

\[\lim_{n \rightarrow \infty} \frac{7+n^2}{n}=\lim_{n \rightarrow \infty} \frac{7}{n}+\frac{n^2}{n}\]

Answer 21

the 7/n goes to 0
and the n^2/n goes to infinity.
so answer is infinity

Answer 22

MUCH THANKS!!!!!