Point A and B are specified by the position vector a and b. Prove that the equation of the plane bisecting the segment AB perpendicularly is
r∙(a-b)=1/2 (|a|^2-|b|^2 )

Question

Point A and B are specified by the position vector a and b. Prove that the equation of the plane bisecting the segment AB perpendicularly is
r∙(a-b)=1/2 (|a|^2-|b|^2 )

anonymous · Answer

r∙(a-b)
is that a dot product or a multiplication?

anonymous · Answer

I believe it is dot.

anonymous · Answer

is there an image or something?

anonymous · Answer

that's the only question.

anonymous · Answer

Hey. I hope you can help me on this one mate! :D @mathslover

mathslover · Answer

http://www.vbforums.com/archive/index.php/t-363648.html

anonymous · Answer

I don't think that answer nor prove the question though. If possible I would like detailed solution. Kind of struggle on vectors.

dominusscholae · Answer

You should probably consider this: the midpoint vector (a+b)/2 as the normal vector of the plane described.

anonymous · Answer

Really need detailed solution please T_T

phi · Answer

Here is one way to do this