Question

int re^(r/2) dr

Answer 1

\[\large \int re^{r/2} dr?\]

Answer 2

\[\int\limits_{}^{}re ^{r/2}dr\]

Answer 3

ahh so it is..

Answer 4

have you tried integration by parts?

Answer 5

I got an ans, but not the book ans

Answer 6

\[2e ^{r/2}(r+1)\]

Answer 7

u=r
du=dr
dv=\[e ^{r/2}\]
v=\[2e ^{r/2}\]

Answer 8

We have to go with Integration By Parts..

Answer 9

right so now use \[uv - \int vdu\]

Answer 10

Is it??

Answer 11

\[r(2e^{r/2}) - \int 2e^{r/2} dr\]
\[2re^{r/2} - 2\int e^{r/2} dr\]
\[2re^{r/2} - 2(2e^{r/2})\]
is tis what you did @manita11 ?

Answer 12

I'm going wrong somewhere. At this point I believe:

\[2re ^{r/2}-2\int\limits_{}^{}e ^{r/2}dr\]

Answer 13

Where is the other 2 from?

Answer 14

the integral of e^r/2

Answer 15

integral of e^r/2 = 2e^r/2 remember?

Answer 16

Is it because in the u-sub part that 2du=dr?

Answer 17

OH. duh. lol

Answer 18

hehe

Answer 19

After I pull the 2 out of the integral I still must integrate e^r/2

Answer 20

yup

Answer 21

\[\textbf{Lagbasallote, LATEX is really a FUN..}\]

Answer 22

haha have you seen @AccessDenied 's tutorial on latex? and it's LG not LAG haha

Answer 23

Ha ha ha sorry for that...
I see it..