Find the antiderivative. f(x) = x^2
use power rule
\[\large \int x^n dx = \frac{x^{n+1}}{n+1}\] do you get that? or do you need more help?
more help please
If you compare your equation to his, what is n?
hint: n is the exponent of x in my example
hmm sorry im still confused
what is the exponent in this problem?
2
2x
2 is the exponent right so what did i do with the exponent in \[x^n dx = \frac{x^{n+1}}{n+1}\]
@student92 anti-derivative, not the derivative. Also, please don't just give out the answer without anything else as that's against the code of conduct: http://openstudy.com/code-of-conduct
put it where n is
okay here's a more visual hint \[\large \int x^3 dx = \frac{x^{3+1}}{3+1} = \frac{x^4}{4}\]
do you see it?
yes
but thats not the antiderivative right?
It's the antiderivative to the example he posted. To prove it you can take the derivative of (X^4}/4 and see if you get X^3 as the result.
oh got it
so do you now know what is \[\int x^2 dx?\]
no...
okay another hint \[\huge \int x^4 dx \implies \frac{x^{4+1}}{4+1} \implies \frac{x^5}{5}\]
so thats the antiderivative
?
It's the anti-derivative of his example. Do you know what an anti-derivative is?
yes, inverse of the derivative
it just follows the rule \[\int x^n dx = \frac{x^{n+1}}{n+1}\] n is the exponent
here's another one... \[\large \int xdx \implies \int x^1 dx \implies \frac{x^{1+1}}{1+1} \implies \frac{x^2}{2}\]
do you see what is \[\int x^2 dx\] yet?
yes i believe so
int(x^3) = (1/4)x^4 int(x^5) = (1/6)x^6 int(x^32) = (1/33)x^33 int(x^2) = ?
(1/3)x^3?
:)
awesome thanks!!!!
fo sure
Now try this one. What function has antiderivative = derivative of the function. If you can work that out. You'll understand how awesome e is.
now take the derivative of that just for fun.
prooving that said function is the ONLY antiderivative = derivative is sort of hard at this point im thinking
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